36x^2+12x+1=4

Solution for 36x^2+12x+1=4 equation:

36x^2+12x+1=4

We move all terms to the left:

36x^2+12x+1-(4)=0

We add all the numbers together, and all the variables

36x^2+12x-3=0

a = 36; b = 12; c = -3;
Δ = b2-4ac
Δ = 122-4·36·(-3)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-24}{2*36}=\frac{-36}{72}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+24}{2*36}=\frac{12}{72}
=1/6
$